Text May 28, 2012 • 2 notes

最後の夜

I was told by people, yesterday, that I have nice arms.
That makes me feel good, ‘cause I was thinking they had slimmed down.
Then they (my friends) started making fun of me, and calling me a bro because I had cut-off sleeves haha

“Hey, Bromón!”

It was hot! \(> 0 <)/
It was a pool party!

Bromón Brostrada Castebrón!!

Photoset May 23,, 2012 • 64 notes

(Source: thelosangeleskings)

Photo May 23, 2012 • 48 notes

(Source: thelosangeleskings)

Photo May 23, 2012 • 34 notes

(Source: thelosangeleskings)

Quote May 23, 2012 • 111 notes

"We’re probably going to have to get a bigger bandwagon."

Dustin Penner (via thelosangeleskings)

Photoset May 23,, 2012 • 82 notes

(Source: thelosangeleskings)

Photoset May 22,, 2012 • 32,310 notes

(Source: degaldo, via heandhiscow)

Text May 18, 2012 • 58 notes

KINGS WIN! 2-1 over the Phoenix Coyotes

thelosangeleskings:

They take a 3-0 series lead in the Western Conference Finals.

Staples Center sure was loud tonight! GKG!!!

Photo May 17, 2012 • 299 notes

Damn you Ramon! I really wanna watch this now.

(Source: i-am-not-real)

Text May 16, 2012

Colligative Properties

Question: If a 0.3165 g sample of a protein dissolves in 161 mL of water at 293 °K, the solution has an osmotic pressure of 10.69 mmHg. Calculate the molar mass (g) of the protein.

Solution: Algebraically rearrange the equation Π = MRT to solve for the molarity of the protein. mmHg need to be converted to atm before solving for M. (1 atm=760 mm Hg.)

Determine how many mol of the protein are present and its molar mass.

Question: If 45.4 g of ethylene glycol are dissolved in 822 g of water solvent, calculate the freezing temperature (if below 0 °C, include the sign) of the solution. The molar freezing point depression constant (K_f) for water is 1.858 °C Kg/mol.

Solution: Use the equation

with m being the molality of the solution to solve for the temperature difference in the freezing point.

The freezing point of the solution will drop 1.65 °C below the normal freezing point of water (0°C) and it will freeze at -1.65 °C.

Question: If 342 g of sodium sulfate are dissolved in 1460 g of water solvent, calculate the magnitude (not the sign) of the boiling point elevation of the solution. The molal boiling point elevation constant (K_b) for water is 0.512 °C Kg/mol.

Solution: Use the equation

to solve for the boiling point elevation. Note: The variable “i” is equal to 3 in this case because each formula unit of Na₂SO₄disassociates into 3 ions.